17y^2-29y=10

Solution for 17y^2-29y=10 equation:

17y^2-29y=10

We move all terms to the left:

17y^2-29y-(10)=0

a = 17; b = -29; c = -10;
Δ = b2-4ac
Δ = -292-4·17·(-10)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-39}{2*17}=\frac{-10}{34}
=-5/17
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+39}{2*17}=\frac{68}{34}
=2
$